CaCO3 + CO2 = ? уравнение реакции Какие продукты образуются в результате взаимодействия CaCO3 + CO2 = ? Надо записать молекулярное уравнение реакции, а также решить задачу. Вот условие: какая масса соли образуется в результате пропускания 18 л диоксида углерода через 150 г раствора карбоната кальция? Какое из веществ будет в избытке?

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Molecular equation: CaCO3 + CO2 = CaCO3

The products formed as a result of the interaction between CaCO3 and CO2 are CaCO3.

To calculate the mass of salt formed when 18 L of carbon dioxide is passed through 150 g of calcium carbonate solution, we need to determine the limiting reactant.

Calculate the number of moles of CaCO3:
Given mass of CaCO3 = 150 g
Molar mass of CaCO3 = 100.09 g/mol
Number of moles of CaCO3 = 150 g / 100.09 g/mol = 1.499 moles

Calculate the number of moles of CO2:
Volume of CO2 gas = 18 L
From ideal gas law, 1 mole of any gas occupies 22.4 L at STP (standard temperature and pressure)
Number of moles of CO2 = 18 L / 22.4 L/mol = 0.804 moles

Determine the limiting reactant:
CaCO3 + CO2 = CaCO3
1 mole of CaCO3 reacts with 1 mole of CO2
Since the number of moles of CaCO3 (1.499 moles) is greater than CO2 (0.804 moles), CaCO3 is the limiting reactant.

Calculate the mass of salt formed:
The molar mass of CaCO3 is 100.09 g/mol
Mass of CaCO3 formed = 1.499 moles * 100.09 g/mol = 150.19 g

Therefore, 150.19 g of salt is formed in the reaction. Calcium carbonate (CaCO3) is the excess reactant.