CaO + CO2 = ? уравнение реакции Какие продукты образуются в результате взаимодействия CaO + CO2 = ? Надо записать молекулярное уравнение реакции, а также решить задачу. Вот условие: какая масса соли образуется из 14 г оксида кальция и 16 л диоксида углерода? Какое из веществ будет в избытке?

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Molecular equation:
CaO + CO2 = CaCO3

To find the mass of salt formed, we need to first balance the equation:
CaO + CO2 = CaCO3
1 CaO + 1 CO2 = 1 CaCO3

Next, we need to find the molar masses of each compound:
CaO: 1 calcium (Ca) = 40.08 g/mol, 1 oxygen (O) = 16.00 g/mol
Molar mass of CaO = 40.08 g/mol + 16.00 g/mol = 56.08 g/mol

CO2: 1 carbon (C) = 12.01 g/mol, 2 oxygen (O) = 2 x 16.00 g/mol = 32.00 g/mol
Molar mass of CO2 = 12.01 g/mol + 32.00 g/mol = 44.01 g/mol

CaCO3: 1 calcium (Ca) = 40.08 g/mol, 1 carbon (C) = 12.01 g/mol, 3 oxygen (O) = 3 x 16.00 g/mol = 48.00 g/mol
Molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + 48.00 g/mol = 100.09 g/mol

Now, we can calculate the amount of CaCO3 formed from the given masses:
Moles of CaO = 14 g / 56.08 g/mol = 0.25 mol
Moles of CO2 = 16 L (at STP, 1 mol of any gas occupies 22.4 L) = 16 / 22.4 = 0.71 mol

From the balanced equation, we see that 1 mol of CaO reacts with 1 mol of CO2 to form 1 mol of CaCO3.
Therefore, the limiting reactant is CaO because it forms the least amount of product.
Amount of CaCO3 formed = 0.25 mol

Mass of CaCO3 formed = 0.25 mol x 100.09 g/mol = 25.02 g

Therefore, 25.02 grams of CaCO3 are formed from the reaction between 14 grams of CaO and 16 liters of CO2.