W(C)=0,8889%, w(H)=?D(пов.)=1,862 CnHm?

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вопрос

To find the weight percentage of Hydrogen (w(H)) in the compound, we first need to calculate the molar mass of the compound (CnHm) given that the weight percentage of Carbon (w(C)) is 0.8889%.

We know that the weight percentage of Carbon is 0.8889% = 0.008889, which means that the weight percentage of Hydrogen is 100% - 0.8889% = 99.1111%.

Now, we can calculate the molar mass of the compound (CnHm) using the weight percentages of Carbon and Hydrogen.

Let's assume the molar mass of Carbon is 12 g/mol and the molar mass of Hydrogen is 1 g/mol.

Molar mass of Carbon = 12 g/mol
Molar mass of Hydrogen = 1 g/mol

Let's assume that the compound has n Carbon atoms and m Hydrogen atoms.

Weight percentage of Carbon = (12 n) / (12 n + 1 m) 100 = 0.8889
Weight percentage of Hydrogen = (1 m) / (12 n + 1 m) 100 = 99.1111

From the above equations, we can solve for n and m.

12n = 0.8889(12n + m)
12n = 10.6668n + 0.8889m
1.3332n = 0.8889m

1m = 1.5n

Therefore, the ratio of Carbon atoms to Hydrogen atoms is 2:3.

So, the compound formula would be C2H3.

And the weight percentage of Hydrogen would be:

w(H) = (3 1) / (2 12 + 3 1) 100 = 0.625%

Therefore, the weight percentage of Hydrogen in the compound C2H3 is 0.625%.