Given:V(C3H6) = 0.1 moles
To find:m (mass), V (volume), and N (number of moles)
To find mass (m) of C3H6:molar mass of C3H6 = 312 (3 carbon atoms) + 61 (6 hydrogen atoms) = 36 + 6 = 42 g/mol
m = n molar massm = 0.1 moles 42 g/molm = 4.2 grams
Therefore, the mass of C3H6 is 4.2 grams.
To find volume (V) using Ideal Gas Law:PV = nRTV = nRT/P
Given:Pressure (P) = ?Volume (V) = ?Number of moles (n) = 0.1 molesGas constant (R) = 0.0821 L.atm/mol.KTemperature (T) = ?
Since the pressure, volume, and temperature are not given, we cannot calculate the volume (V) using the Ideal Gas Law without this information.
To find number of moles (N):N = V / molar massN = 0.1 moles
Therefore, the number of moles of C3H6 is 0.1 moles.
Given:
V(C3H6) = 0.1 moles
To find:
m (mass), V (volume), and N (number of moles)
To find mass (m) of C3H6:
molar mass of C3H6 = 312 (3 carbon atoms) + 61 (6 hydrogen atoms) = 36 + 6 = 42 g/mol
m = n molar mass
m = 0.1 moles 42 g/mol
m = 4.2 grams
Therefore, the mass of C3H6 is 4.2 grams.
To find volume (V) using Ideal Gas Law:
PV = nRT
V = nRT/P
Given:
Pressure (P) = ?
Volume (V) = ?
Number of moles (n) = 0.1 moles
Gas constant (R) = 0.0821 L.atm/mol.K
Temperature (T) = ?
Since the pressure, volume, and temperature are not given, we cannot calculate the volume (V) using the Ideal Gas Law without this information.
To find number of moles (N):
N = V / molar mass
N = 0.1 moles
Therefore, the number of moles of C3H6 is 0.1 moles.