M (CaO)=9г т к (CaCl2)

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вопрос

To find the amount of calcium chloride produced when 9g of calcium oxide is reacted, we need to first calculate the molar mass of each compound.

Molar mass of CaO (calcium oxide)
Ca = 40.08 g/mo
O = 16.00 g/mo
Molar mass of CaO = 40.08 + 16.00 = 56.08 g/mol

Next, we need to balance the chemical equation for the reaction between calcium oxide and hydrochloric acid to form calcium chloride:

CaO + 2HCl -> CaCl2 + H2O

From the balanced equation, we see that 1 mol of CaO produces 1 mol of CaCl2.

Now we can calculate the amount of calcium chloride produced from 9g of calcium oxide:

1 mol of CaO = 56.08
9g of CaO * (1 mol CaCl2 / 56.08g CaO) = 0.160 mol CaCl2

Finally, we convert this amount into grams of calcium chloride:

Molar mass of CaCl2
Ca = 40.08 g/mo
Cl = 35.45 g/mo
Molar mass of CaCl2 = 40.08 + 2(35.45) = 110.98 g/mol

0.160 mol CaCl2 * 110.98 g/mol = 17.76g

Therefore, 9g of calcium oxide will produce 17.76g of calcium chloride.