6х²+7х*3=0; 3х²-5х-2=0

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вопрос

To solve the equations:

1) 6x² + 7x - 3 = 0

To solve this quadratic equation, we can use the quadratic formula:
x = (-b ± √(b² - 4ac)) / 2a

In this case, a = 6, b = 7, and c = -3

Plugging in the values:
x = (-7 ± √(7² - 46(-3))) / 2*6
x = (-7 ± √(49 + 72)) / 12
x = (-7 ± √121) / 12
x = (-7 ± 11) / 12

There are two possible solutions:
x = (-7 + 11) / 12 = 4 / 12 = 1/3
x = (-7 - 11) / 12 = -18 / 12 = -1.5

Therefore, the solutions are x = 1/3 and x = -1.5

2) 3x² - 5x - 2 = 0

To solve this quadratic equation, we can factor or use the quadratic formula.

Factoring:
(3x + 1)(x - 2) = 0

Setting each factor to zero:
3x + 1 = 0
x = -1/3

x - 2 = 0
x = 2

Therefore, the solutions are x = -1/3 and x = 2.