6x^y(2xy-5)+3x(2xy-5)=2x(6x^y^-5)-25

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вопрос

First, distribute the terms in the equation:

6x^y(2xy) - 6x^y(5) + 3x(2xy) - 3x(5) = 2x(6x^y) - 2x(5) - 25

Simplify each term:

12x^(y+1)y - 30x^y + 6x^2y - 15x = 12x^(y+1) - 10x - 25

Now we have:

12x^(y+1)y + 6x^2y - 30x^y + 6x^2 - 15x + 10x + 25 = 0

Rearrange the terms:

12x^(y+1)y - 30x^y + 6x^2y + 6x^2 - 15x + 10x + 25 = 0

Combine like terms:

12x^(y+1)y - 30x^y + 6x^2y + 6x^2 - 5x + 25 = 0

Therefore, the final simplified equation is:

12x^(y+1)y - 30x^y + 6x^2y + 6x^2 - 5x + 25 = 0