To solve the equation 2sin(π/2 - x) - √3 = 0, we first need to isolate the sine term.
2sin(π/2 - x) = √3
sin(π/2 - x) = √3 / 2
Now, we recall that sin(π/3) = √3 / 2. Therefore,
π/2 - x = π/3
Solving for x:
x = π/2 - π/3
x = π/6
Therefore, the solution to the equation is x = π/6.
To solve the equation 2sin(π/2 - x) - √3 = 0, we first need to isolate the sine term.
2sin(π/2 - x) = √3
sin(π/2 - x) = √3 / 2
Now, we recall that sin(π/3) = √3 / 2. Therefore,
π/2 - x = π/3
Solving for x:
x = π/2 - π/3
x = π/6
Therefore, the solution to the equation is x = π/6.