1/3(3x-6)-2/7(7x-21)=9

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вопрос

To solve this equation, we first need to distribute the coefficients of each term:

1/3(3x) - 1/3(6) - 2/7(7x) + 2/7(21) = 9
x - 2 - 2x + 6 = 9

Now, combine like terms:

-x + 4 = 9

Subtract 4 from both sides:

-x = 5

Divide by -1 to solve for x:

x = -5

Therefore, the solution to the equation is x = -5.