(x²-5x+7)²- (x²-5x+7)=0

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вопрос

Let's first simplify the expression by multiplying out (x²-5x+7)²:

(x²-5x+7)² = (x²-5x+7)(x²-5x+7)
= x⁴ - 5x³ + 7x² - 5x³ + 25x² - 35x + 7x² - 35x + 49
= x⁴ - 10x³ + 39x² - 70x + 49

Now we can substitute this back into the original equation:

(x⁴ - 10x³ + 39x² - 70x + 49) - (x²-5x+7) = 0
x⁴ - 10x³ + 39x² - 70x + 49 - x² + 5x - 7 = 0
x⁴ - 10x³ + 38x² - 65x + 42 = 0

This is a fourth-degree polynomial equation. It can be difficult to solve without using numerical methods or graphing software.