To solve this inequality, we first need to find the range of values for the given expression cos (π/4 - x).
Using the trigonometric identity cos (a - b) = cos a cos b + sin a sin b, we get:
cos (π/4 - x) = cos π/4 cos x + sin π/4 sin x
Since cos π/4 = sin π/4 = √2/2, we have:
cos (π/4 - x) = (√2/2)(√2/2) + (√2/2)(sin x)cos (π/4 - x) = 2/4 + (√2/2)(sin x)cos (π/4 - x) = 1/2 + (√2/2)(sin x)
Now, our inequality is:
1/2 + (√2/2)(sin x) < √2/2
Subtracting 1/2 from both sides, we get:
(√2/2)(sin x) < √2/2 - 1/2(√2/2)(sin x) < 1/2
Dividing by √2/2, we get:
sin x < 1
This means that the inequality cos (π/4 - x) < √2/2 holds for all values of x where sin x < 1.
Therefore, the solution to the inequality cos (π/4 - x) < √2/2 is all real numbers x.
To solve this inequality, we first need to find the range of values for the given expression cos (π/4 - x).
Using the trigonometric identity cos (a - b) = cos a cos b + sin a sin b, we get:
cos (π/4 - x) = cos π/4 cos x + sin π/4 sin x
Since cos π/4 = sin π/4 = √2/2, we have:
cos (π/4 - x) = (√2/2)(√2/2) + (√2/2)(sin x)
cos (π/4 - x) = 2/4 + (√2/2)(sin x)
cos (π/4 - x) = 1/2 + (√2/2)(sin x)
Now, our inequality is:
1/2 + (√2/2)(sin x) < √2/2
Subtracting 1/2 from both sides, we get:
(√2/2)(sin x) < √2/2 - 1/2
(√2/2)(sin x) < 1/2
Dividing by √2/2, we get:
sin x < 1
This means that the inequality cos (π/4 - x) < √2/2 holds for all values of x where sin x < 1.
Therefore, the solution to the inequality cos (π/4 - x) < √2/2 is all real numbers x.