To solve this logarithmic equation, we can use the property of logarithms that states if log_a(b) = log_a(c), then b = c.
Given:
log4(4+7x) = log4(1+5x) + 1
Using the property mentioned above, we get:
4+7x = 1+5x + 4
Now, we can simplify the equation:
7x - 5x = 1
2x = 1
x = 1/2
Therefore, the solution to the equation log4(4+7x) = log4(1+5x) + 1 is x = 1/2.
To solve this logarithmic equation, we can use the property of logarithms that states if log_a(b) = log_a(c), then b = c.
Given:
log4(4+7x) = log4(1+5x) + 1
Using the property mentioned above, we get:
4+7x = 1+5x + 4
Now, we can simplify the equation:
7x - 5x = 1
2x = 1
x = 1/2
Therefore, the solution to the equation log4(4+7x) = log4(1+5x) + 1 is x = 1/2.