((х+1)(х+2))/(х-3)≥0

Предыдущий
вопрос Следующий
вопрос

To solve the inequality, we can first find the critical points by setting the numerator and denominator equal to 0:

(x+1)(x+2) = 0
x = -1 or x = -2

(x - 3) = 0
x = 3

Now we can test the intervals between these critical points and outside them to determine when the inequality is greater than or equal to 0:

For x < -2:
(-)(-) / (-) = positive

For -2 < x < -1:
(-)(+) / (-) = negative

For -1 < x < 3:
(+)(+) / (-) = negative

For x > 3:
(+)(+) / (+) = positive

Therefore, the solution to the inequality is:

x ≤ -2 or x ≥ 3