To solve this system of equations, we can use the method of substitution or elimination.
First, let's solve for y in the first equation:4x - 3y = -31-3y = -4x - 31y = (4/3)x + 31/3
Now, substitute y = (4/3)x + 31/3 into the second equation:9x + 5((4/3)x + 31/3) = -119x + (20/3)x + 155/3 = -11(27/3)x + (20/3)x + 155/3 = -11(47/3)x + 155/3 = -11(47/3)x = -11 - 155/3(47/3)x = -33/3 - 155/3(47/3)x = -188/3x = -188/3 * 3/47x = -188/47
Now, substitute x = -188/47 back into y = (4/3)x + 31/3 to find y:y = (4/3)(-188/47) + 31/3y = -250/47 + 31/3y = -250/47 + 155/47y = -95/47
Therefore, the solution to the system of equations is x = -188/47 and y = -95/47.
To solve this system of equations, we can use the method of substitution or elimination.
First, let's solve for y in the first equation:
4x - 3y = -31
-3y = -4x - 31
y = (4/3)x + 31/3
Now, substitute y = (4/3)x + 31/3 into the second equation:
9x + 5((4/3)x + 31/3) = -11
9x + (20/3)x + 155/3 = -11
(27/3)x + (20/3)x + 155/3 = -11
(47/3)x + 155/3 = -11
(47/3)x = -11 - 155/3
(47/3)x = -33/3 - 155/3
(47/3)x = -188/3
x = -188/3 * 3/47
x = -188/47
Now, substitute x = -188/47 back into y = (4/3)x + 31/3 to find y:
y = (4/3)(-188/47) + 31/3
y = -250/47 + 31/3
y = -250/47 + 155/47
y = -95/47
Therefore, the solution to the system of equations is x = -188/47 and y = -95/47.