To solve this system of equations, we can use the method of substitution or elimination.
First, let's solve for y in the first equation4x - 3y = -3-3y = -4x - 3y = (4/3)x + 31/3
Now, substitute y = (4/3)x + 31/3 into the second equation9x + 5((4/3)x + 31/3) = -19x + (20/3)x + 155/3 = -1(27/3)x + (20/3)x + 155/3 = -1(47/3)x + 155/3 = -1(47/3)x = -11 - 155/(47/3)x = -33/3 - 155/(47/3)x = -188/x = -188/3 * 3/4x = -188/47
Now, substitute x = -188/47 back into y = (4/3)x + 31/3 to find yy = (4/3)(-188/47) + 31/y = -250/47 + 31/y = -250/47 + 155/4y = -95/47
Therefore, the solution to the system of equations is x = -188/47 and y = -95/47.
To solve this system of equations, we can use the method of substitution or elimination.
First, let's solve for y in the first equation
4x - 3y = -3
-3y = -4x - 3
y = (4/3)x + 31/3
Now, substitute y = (4/3)x + 31/3 into the second equation
9x + 5((4/3)x + 31/3) = -1
9x + (20/3)x + 155/3 = -1
(27/3)x + (20/3)x + 155/3 = -1
(47/3)x + 155/3 = -1
(47/3)x = -11 - 155/
(47/3)x = -33/3 - 155/
(47/3)x = -188/
x = -188/3 * 3/4
x = -188/47
Now, substitute x = -188/47 back into y = (4/3)x + 31/3 to find y
y = (4/3)(-188/47) + 31/
y = -250/47 + 31/
y = -250/47 + 155/4
y = -95/47
Therefore, the solution to the system of equations is x = -188/47 and y = -95/47.