(4х+1)(4х-1)+(2х-3)²=5х(4х-1)

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вопрос

Let's expand and simplify both sides of the equation to verify if they are equal:

Left side:
(4x+1)(4x-1) + (2x-3)²
= 16x² - 4x + 4x - 1 + 4x² - 12x + 9
= 16x² - 1 + 4x² - 8x + 9
= 20x² - 8x + 8

Right side:
5x(4x-1)
= 20x² - 5x

Now let's compare the left and right sides of the equation:
20x² - 8x + 8 = 20x² - 5x

Since the left side is not equal to the right side, the equation is not true.