(х+2)²-(х+2)(х-5)<14х-7

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вопрос

First, let's simplify the left side of the inequality:

(х+2)² - (х+2)(х-5)
= (x+2)(x+2) - (x+2)(x-5)
= x² + 4x + 4 - (x² - 3x - 10)
= x² + 4x + 4 - x² + 3x + 10
= 7x + 14

Now, our inequality becomes:

7x + 14 < 14x - 7

Next, let's isolate x on one side of the inequality. We can do this by subtracting 7x from both sides:

14 < 7x - 7

Now, add 7 to both sides:

21 < 7x

Divide by 7 on both sides to solve for x:

3 < x

Therefore, the solution for the inequality (х+2)²-(х+2)(х-5) < 14х-7 is x > 3.