1)-5/12х=0 2)(х-3)(х+4)=0

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вопрос

1) To solve for x in the equation -5/12x = 0, we can first multiply both sides by 12 to get rid of the fraction:

-5x = 0

Next, divide both sides by -5 to isolate x:

x = 0

Therefore, the solution to the equation is x = 0.

2) To solve the quadratic equation (x-3)(x+4) = 0, we can use the zero-product property which states that if the product of two factors is zero, then at least one of the factors must be zero.

Setting each factor to zero:

x - 3 = 0
x = 3

and

x + 4 = 0
x = -4

Therefore, the solutions to the equation are x = 3 and x = -4.