1) lim tg(3-x) / 2+x x->2 2) lim x2-2x-9 / x3+1 x->-1

Предыдущий
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вопрос

1) lim tg(3-x) / 2+x as x approaches 2

To find this limit, we can simply substitute x = 2 into the expression:

tg(3-2) / 2+2
= tg(1) / 4

The tangent of 1 is a specific value that we can look up, but since we are not provided with that information in this case, we cannot simplify the expression further. Therefore, the limit of tg(3-x) / 2+x as x approaches 2 is tg(1) / 4.

2) lim (x^2 - 2x - 9) / (x^3 + 1) as x approaches -1

To find this limit, we can again simply substitute x = -1 into the expression:

(-1)^2 - 2(-1) - 9 / (-1)^3 + 1
= 1 + 2 - 9 / -1 + 1
= -6 / 0

Since division by zero is undefined, the limit of (x^2 - 2x - 9) / (x^3 + 1) as x approaches -1 does not exist.