To solve the quadratic equation 2x^2 + 3x - 4 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = 2, b = 3, and c = -4.
Plugging these values into the quadratic formula, we get:
x = (-3 ± √(3^2 - 42-4)) / (2*2)x = (-3 ± √(9 + 32)) / 4x = (-3 ± √41) / 4
So the solutions to the quadratic equation are:
x = (-3 + √41) / 4 and x = (-3 - √41) / 4.
To solve the quadratic equation 2x^2 + 3x - 4 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = 2, b = 3, and c = -4.
Plugging these values into the quadratic formula, we get:
x = (-3 ± √(3^2 - 42-4)) / (2*2)
x = (-3 ± √(9 + 32)) / 4
x = (-3 ± √41) / 4
So the solutions to the quadratic equation are:
x = (-3 + √41) / 4 and x = (-3 - √41) / 4.