Log1/ 2x^2-log1/2x=6

Предыдущий
вопрос Следующий
вопрос

To solve this problem, we can use the properties of logarithms to combine the two logarithmic terms into one.

First, let's rewrite the equation using the properties of logarithms:

log1/2(x^2) - log1/2(x) = 6

Next, we can use the property of logarithms that states: log_b(x) - log_b(y) = log_b(x/y)

Therefore, we can rewrite the equation as:

log1/2(x^2 / x) = 6

Simplify the expression inside the logarithm:

log1/2(x) = 6

Now, since the base of the logarithm is 1/2, we can rewrite the equation in exponential form:

1/2^6 = x

x = 1/64

So, the solution to the equation log1/2(x^2) - log1/2(x) = 6 is x = 1/64.