(6х^3-1)^2-(4х^3-1)(9x^3+5)+23x^3=6

Предыдущий
вопрос Следующий
вопрос

Expanding the terms, we get:

(6x^3 - 1)^2 = (6x^3 - 1)(6x^3 - 1) = 36x^6 - 12x^3 - 12x^3 + 1 = 36x^6 - 24x^3 + 1

(4x^3 - 1)(9x^3 + 5) = 36x^6 + 20x^3 - 9x^3 - 5 = 36x^6 + 11x^3 - 5

And the equation becomes:

36x^6 - 24x^3 + 1 - (36x^6 + 11x^3 - 5) + 23x^3 = 6

Simplifying further, we get:

-24x^3 + 1 - 36x^6 - 11x^3 + 5 + 23x^3 = 6

-12x^3 - 36x^6 + 6 = 6

Combining the terms:

-12x^3 - 36x^6 = 0

Therefore, the final equation is:

12x^3 + 36x^6 = 0