(2-x)(3-x)=(x+2)(x-5)

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Expanding both sides of the equation:

(2-x)(3-x) = 6 - 2x - 3x + x^2
= 6 - 5x + x^2

(x+2)(x-5) = x^2 - 5x + 2x -10
= x^2 - 3x - 10

Now, equating the two sides:

6 - 5x + x^2 = x^2 - 3x - 10

Rearranging the terms:

6 - 5x = -3x - 10

Adding 3x to both sides:

6 - 2x = -10

Subtracting 6 from both sides:

-2x = -16

Dividing by -2:

x = 8

Therefore, the solution to the equation is x = 8.