Let the first term of the arithmetic progression be a and the common difference be d.
Given:a + 13d = 135 (14th term is 135)14a + 91d = 980 (sum of the first 14 terms is 980)
Solving the two equations simultaneously, we get:a = 5, d = 10
Therefore, the first term of the arithmetic progression is 5.
Let the first term of the arithmetic progression be a and the common difference be d.
Given:
a + 13d = 135 (14th term is 135)
14a + 91d = 980 (sum of the first 14 terms is 980)
Solving the two equations simultaneously, we get:
a = 5, d = 10
Therefore, the first term of the arithmetic progression is 5.