0,3х - х2 = 0. 12 - 17х - 5х2 = 0. 7х - 4х2 = -15.

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To solve these quadratic equations, we can rearrange them into standard form (ax^2 + bx + c = 0) and then use the quadratic formula to find the solutions.

0.3x - x^2 = 0
Rearrange the equation:
x^2 - 0.3x = 0
Apply the quadratic formula:
x = (0.3 ± sqrt((-0.3)^2 - 410)) / 2*1
x = (0.3 ± sqrt(0.09)) / 2
x = (0.3 ± 0.3) / 2
x = 0.6 / 2 = 0.3
The solutions to this equation are x = 0.3.

12 - 17x - 5x^2 = 0
Rearrange the equation:
5x^2 + 17x - 12 = 0
Apply the quadratic formula:
x = (-17 ± sqrt(17^2 - 45(-12))) / 2*5
x = (-17 ± sqrt(289 + 240)) / 10
x = (-17 ± sqrt(529)) / 10
x = (-17 ± 23) / 10
The solutions are x = (23 - 17) / 10 = 0.6 and x = (-23 - 17) / 10 = -4.

7x - 4x^2 = -15
Rearrange the equation:
4x^2 - 7x + 15 = 0
Apply the quadratic formula:
x = (7 ± sqrt((-7)^2 - 4415)) / 2*4
x = (7 ± sqrt(49 - 240)) / 8
x = (7 ± sqrt(-191)) / 8
Since the square root of -191 is imaginary, the solutions are complex numbers and cannot be expressed in the form of real numbers.