A)(x-7)^2+3=(2+x)(x-2) б)x+x/12=13/2 с)-25x^2-16=0

Предыдущий
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вопрос

A) (x-7)^2 + 3 = (2+x)(x-2)
Expanding the left side:
(x-7)(x-7) + 3 = (2+x)(x-2)
x^2 - 7x - 7x + 49 + 3 = 2x - 4x - 4
x^2 - 14x + 52 = 2x - 4x - 4
x^2 - 14x + 52 = -2x - 4
x^2 - 12x + 56 = 0

B) x + x/12 = 13/2
First, rewrite x/12 as x (1/12):
x + x (1/12) = 13/2
Multiplying both sides by 12 to get rid of the fraction:
12x + x = 78
13x = 78
x = 6

C) -25x^2 - 16 = 0
To solve this equation, add 16 to both sides:
-25x^2 = 16
Divide by -25 to isolate x^2:
x^2 = -16/25
Take the square root of both sides:
x = ±√(-16/25)
x = ±(4i/5)