2cos*(3x- π/6) +√3=0

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To solve the equation 2cos(3x - π/6) + √3 = 0, we can first isolate the cosine term:

2cos(3x - π/6) = -√3

Next, divide both sides by 2:

cos(3x - π/6) = -√3 / 2

Now, we want to find the values of x that satisfy this equation. Since we have a cosine function and we know that the cosine function is periodic with a period of 2π, we can say that:

3x - π/6 = ±π/6 + 2πn

Where n is an integer. Solving for x, we get:

3x = ±π/6 + π/6 + 2πn

3x = π/3 + 2πn

x = π/9 + 2πn/3

So, the solution to the equation 2cos(3x - π/6) + √3 = 0 is:

x = π/9 + 2πn/3, where n is an integer.