To solve the equations ׳-5ײ-×+5=0 and ׳=2ײ+4×-8, we can substitute the second equation into the first equation.
(2ײ+4×-8)-5ײ-×+5 = 0-3ײ + 3× - 8 = 0
Now, we can solve this quadratic equation by factoring or using the quadratic formula:
-3ײ + 3× - 8 = 0(3× - 4)(-× + 2) = 03× - 4 = 0 or -× + 2 = 0× = 4/3 or × = -2
Therefore, the solutions for the equations are × = 4/3 and × = -2.
To solve the equations ׳-5ײ-×+5=0 and ׳=2ײ+4×-8, we can substitute the second equation into the first equation.
(2ײ+4×-8)-5ײ-×+5 = 0
-3ײ + 3× - 8 = 0
Now, we can solve this quadratic equation by factoring or using the quadratic formula:
-3ײ + 3× - 8 = 0
(3× - 4)(-× + 2) = 0
3× - 4 = 0 or -× + 2 = 0
× = 4/3 or × = -2
Therefore, the solutions for the equations are × = 4/3 and × = -2.