2sinx=V3 V - корень квадратный

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вопрос

To solve the equation 2sinx = √3, we need to isolate the sinx term by dividing both sides by 2:

sinx = √3/2

Now, we need to find the angles in the unit circle where sinx = √3/2. The sine function is positive in the first and second quadrants.

In the unit circle, sin(30°) = 1/2 and sin(60°) = √3/2.

Therefore, the solutions to the equation sinx = √3/2 are x = 60° + 360°n and x = 120° + 360°n, where n is an integer.