1)sin 750°ctg50°+tg(-120°) 4)sin(π-t)+cos(3π+t)>-√3 16 (-55) __ 2)tg __-cos____ 2 3 (6) 3)упростить π ctg(π+α) сos(__+α) 2

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1) sin 750° = sin(360° + 390°) = sin(390°) = sin(390° - 360°) = sin 30° = 1/2
ctg50° = 1/tan50° = 1/(sin50°/cos50°) = cos50°/sin50° = √3
tg(-120°) = -tan120° = -sin120°/cos120° = -(√3 / 2) / (-1/2) = √3

Therefore, sin 750° + ctg50° + tg(-120°) = 1/2 + √3 + √3 = 1/2 + 2√3

2) tg -cos__ = tg x - cos y
When x = 3π, y = π
tg 3π - cos π = 0 - (-1) = 1

3) Simplify π ctg(π+α) cos(__+α) = π cot(π+α) cos(π+α)
cot(π+α) = cotπ cotα - 1 = 0 * cotα - 1 = -1
cos(π+α) = -cosα
Therefore, the expression simplifies to -π cosα

Hope this helps. Let me know if you need further clarification.