To find the solutions to these equations, we can use the double angle identities for cosine and sine.
Using the double angle identity for cosine, cos(2x) = 2cos²x - 1, we can rewrite the equation as:
cos²x - sin²x - 4cos²x + 2 = -3cos²x - sin²x + 2 = -3(1 - sin²x) - sin²x + 2 = -3 + 3sin²x - sin²x + 2 = 2sin²x - 1 = sin²x = 1/sinx = ±sqrt(1/2x = π/4, 3π/4, 5π/4, 7π/4
Using the double angle identity for sine, sin(2x) = 2sinxcosx, we can rewrite the equation as:
cos²x - sinxcosx = cosx(cosx - sinx) = cosx = 0 or cosx = sinx
For cosx = 0, x = π/2
For cosx = sinx, we square both sidescos²x = sin²1 - sin²x = sin²1 = 2sin²sin²x = 1/sinx = ±sqrt(1/2x = π/4, 3π/4
To find the solutions to these equations, we can use the double angle identities for cosine and sine.
For the equation cos²x - sin²x - 2cos²2x = 0:Using the double angle identity for cosine, cos(2x) = 2cos²x - 1, we can rewrite the equation as:
cos²x - sin²x - 4cos²x + 2 =
For the equation cos²x - ½sin2x = 0:-3cos²x - sin²x + 2 =
-3(1 - sin²x) - sin²x + 2 =
-3 + 3sin²x - sin²x + 2 =
2sin²x - 1 =
sin²x = 1/
sinx = ±sqrt(1/2
x = π/4, 3π/4, 5π/4, 7π/4
Using the double angle identity for sine, sin(2x) = 2sinxcosx, we can rewrite the equation as:
cos²x - sinxcosx =
cosx(cosx - sinx) =
cosx = 0 or cosx = sinx
For cosx = 0, x = π/2
For cosx = sinx, we square both sides
cos²x = sin²
1 - sin²x = sin²
1 = 2sin²
sin²x = 1/
sinx = ±sqrt(1/2
x = π/4, 3π/4