Log(4)48-log(4)3+6^log(6)5

Предыдущий
вопрос Следующий
вопрос

To solve this logarithmic expression, we can use the properties of logarithms:

Given expression: log(4)48 - log(4)3 + 6^log(6)5

Firstly, let's simplify the logarithmic terms using the properties of logarithms:
log(4)48 = log(48)/log(4)

Now, we can simplify the expression further:
log(48)/log(4) - log(3)/log(4) + 6^log(6)5

Now, let's calculate log(48) / log(4):
log(48) is log base 10 (since the base is not specified) of 48
log(48) ≈ 1.6812

log(4) is log base 10 of 4, which equals 0.6021

Therefore, log(48)/log(4) ≈ 1.6812 / 0.6021 ≈ 2.7947

Next, let's calculate log(3) / log(4):
log(3) is log base 10 of 3
log(3) ≈ 0.4771

Thus, log(3)/log(4) ≈ 0.4771 / 0.6021 ≈ 0.7917

Finally, the expression becomes:
2.7947 - 0.7917 + 6^log(6)5

Now, calculate the value of 6^log(6)5:
6^log(6)5 = 6^5 ≈ 7776

Therefore, the final simplified expression is:
2.7947 - 0.7917 + 7776 ≈ 7778.0030

Thus, log(4)48 - log(4)3 + 6^log(6)5 is approximately equal to 7778.0030.