To find the value of "a" in the equation 4x² - 25x + 36 = 4(x - 4)(x - a), we need to expand the right side of the equation and then compare it to the left side.
Expanding the right side: 4(x - 4)(x - a) = 4(x² - ax - 4x + 4a) = 4(x² - (a+4)x + 4a) = 4x² - 4(a+4)x + 16a
Now we can compare this to the original equation: 4x² - 25x + 36
Equating the coefficients of x²: 4 = 4
Equating the coefficients of x: -4(a+4) = -25 -4a - 16 = -25 -4a = -9 a = 9/4
Therefore, the value of "a" in the equation 4x² - 25x + 36 = 4(x - 4)(x - a) is a = 9/4.
To find the value of "a" in the equation 4x² - 25x + 36 = 4(x - 4)(x - a), we need to expand the right side of the equation and then compare it to the left side.
Expanding the right side:
4(x - 4)(x - a)
= 4(x² - ax - 4x + 4a)
= 4(x² - (a+4)x + 4a)
= 4x² - 4(a+4)x + 16a
Now we can compare this to the original equation:
4x² - 25x + 36
Equating the coefficients of x²:
4 = 4
Equating the coefficients of x:
-4(a+4) = -25
-4a - 16 = -25
-4a = -9
a = 9/4
Therefore, the value of "a" in the equation 4x² - 25x + 36 = 4(x - 4)(x - a) is a = 9/4.