{3x-y=10 {x/3-y+1/5=1

Предыдущий
вопрос Следующий
вопрос

To solve this system of equations, we can use the substitution method.

From the first equation, we can rearrange it to solve for y:
3x - y = 10
y = 3x - 10

Now, we can substitute this expression for y into the second equation:
x/3 - (3x - 10) + 1/5 = 1

Now, we can solve for x:
x/3 - 3x + 10 + 1/5 = 1
Multiply all terms by 15 to get rid of the fraction:
5x - 45x + 150 + 3 = 15
-40x + 153 = 15
-40x = -138
x = 138/40
x = 69/20

Now that we have found the value of x, we can substitute it back into the expression for y:
y = 3*(69/20) - 10
y = 207/20 - 200/20
y = 7/20

Therefore, the solution to the system of equations is:
x = 69/20
y = 7/20