(√∛25)³ = (25)^(1/6) = 5^(3/2) = 5√5
(a^√3+1) * 1/a⁴⁺√3 = a^(√3 + 1)/a^(4+√3) = a√3/a^4√3 = a√3 / a^(12) = 1/a^(12-√3) = 1/a^(12-√3)
(√∛25)³ = (25)^(1/6) = 5^(3/2) = 5√5
(a^√3+1) * 1/a⁴⁺√3 = a^(√3 + 1)/a^(4+√3) = a√3/a^4√3 = a√3 / a^(12) = 1/a^(12-√3) = 1/a^(12-√3)