A)(8x-16)(4x-12)=0 b)(2x-6)(-3x+5)=0

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вопрос

a) To find the solutions for (8x-16)(4x-12)=0, we need to set each factor to 0 and solve for x.

First factor:
8x - 16 = 0
8x = 16
x = 2

Second factor:
4x - 12 = 0
4x = 12
x = 3

Therefore, the solutions for (8x-16)(4x-12)=0 are x = 2 and x = 3.

b) To find the solutions for (2x-6)(-3x+5)=0, we follow the same process as above.

First factor:
2x - 6 = 0
2x = 6
x = 3

Second factor:
-3x + 5 = 0
-3x = -5
x = 5/3

Therefore, the solutions for (2x-6)(-3x+5)=0 are x = 3 and x = 5/3.