X^2-81x=0(x-4)^2-x^2>0

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вопрос

To solve the inequality (x-4)^2 - x^2 > 0, we can first expand and simplify the left side:

(x-4)^2 - x^2
= x^2 - 8x + 16 - x^2
= -8x + 16

Now we have the inequality -8x + 16 > 0. We can solve this by isolating x:

-8x + 16 > 0
-8x > -16
x < 2

Therefore, the solution to the inequality (x-4)^2 - x^2 > 0 is x < 2.