To solve this equation, we first need to use the property of logarithms that states if log a (b) = log a (c), then b = c.
So in this case,4x - 6 = 2x - 4
Solving for x, we get:4x - 2x = -4 + 62x = 2x = 1
Therefore, the solution to the equation log7(4x-6) = log7(2x-4) is x = 1.
To solve this equation, we first need to use the property of logarithms that states if log a (b) = log a (c), then b = c.
So in this case,
4x - 6 = 2x - 4
Solving for x, we get:
4x - 2x = -4 + 6
2x = 2
x = 1
Therefore, the solution to the equation log7(4x-6) = log7(2x-4) is x = 1.