Let's first simplify each term in the equation:

(×+2)³ = (×+2)(×+2)(×+2) = (ײ+4×+4)(×+2) = ׳ + 6ײ + 12× + 8

×(3×-1)² = ×(9ײ-6×+1) = 9׳ - 6ײ + ×

(2×+1)(4ײ-2×+1) = 8׳ - 4ײ + 2× + 4ײ - 2× + 1 = 8׳

Now, substitute these simplified terms back into the equation:

(׳ + 6ײ + 12× + 8) - (9׳ - 6ײ + ×) + 8׳ = 42

׳ + 6ײ + 12× + 8 - 9׳ + 6ײ - × + 8׳ = 42

-3׳ + 12ײ + 11× + 8 = 42

-3׳ + 12ײ + 11× - 34 = 0

This is the simplified form of the equation.