2(x+3)(x-2) - (2x+1)(x-3) - 7 = 0

Expanding the terms:

2(x^2 - 2x + 3x - 6) - (2x^2 - 3x + x -3) - 7 = 0

2(x^2 + x - 6) - (2x^2 - 2x - 3) - 7 = 0

2x^2 + 2x - 12 - 2x^2 + 2x + 3 - 7 = 0

5 - 12 - 7 = 0

-14 = 0

Therefore, the given equation does not have a solution.