Let's expand both sides of the equation:
3(x+1)(x+2) = 3(x^2 + 2x + x + 2= 3(x^2 + 3x + 2= 3x^2 + 9x + 6
(3x-4)(x+2) = 3x^2 + 6x - 4x - = 3x^2 + 2x - 8
Now, we can substitute these expanded forms back into the original equation:
3x^2 + 9x + 6 - (3x^2 + 2x - 8) = 33x^2 + 9x + 6 - 3x^2 - 2x + 8 = 37x + 14 = 37x = 2x = 22/7
Therefore, the solution to the equation is x = 22/7.
Let's expand both sides of the equation:
3(x+1)(x+2) = 3(x^2 + 2x + x + 2
= 3(x^2 + 3x + 2
= 3x^2 + 9x + 6
(3x-4)(x+2) = 3x^2 + 6x - 4x -
= 3x^2 + 2x - 8
Now, we can substitute these expanded forms back into the original equation:
3x^2 + 9x + 6 - (3x^2 + 2x - 8) = 3
3x^2 + 9x + 6 - 3x^2 - 2x + 8 = 3
7x + 14 = 3
7x = 2
x = 22/7
Therefore, the solution to the equation is x = 22/7.