To solve the inequality log2(3x-1) > log2(2-7x), we can start by applying the property of logarithms that states loga(x) > loga(y) if and only if x > y.
Therefore, we have:
3x - 1 > 2 - 7x
Now, let's solve for x:
3x + 7x > 2 + 1
10x > 3
x > 3/10
Therefore, the solution to the inequality log2(3x-1) > log2(2-7x) is x > 3/10.
To solve the inequality log2(3x-1) > log2(2-7x), we can start by applying the property of logarithms that states loga(x) > loga(y) if and only if x > y.
Therefore, we have:
3x - 1 > 2 - 7x
Now, let's solve for x:
3x + 7x > 2 + 1
10x > 3
x > 3/10
Therefore, the solution to the inequality log2(3x-1) > log2(2-7x) is x > 3/10.