To solve this equation, we first need to factor both the numerator and the denominator.
Numerator: x^2 - 3x + 2 can be factored as (x - 1)(x - 2)Denominator: x^2 - 4 can be factored as (x + 2)(x - 2)
Therefore, the equation becomes:
(x - 1)(x - 2) / (x + 2)(x - 2) = 0
Now, we can simplify this by cancelling out the common factor of (x - 2) in the numerator and denominator:
(x - 1) / (x + 2) = 0
To find the values of x that satisfy this equation, we set the numerator equal to zero:
x - 1 = 0x = 1
Therefore, the solution to the equation x^2 - 3x + 2 / x^2 - 4 = 0 is x = 1.
To solve this equation, we first need to factor both the numerator and the denominator.
Numerator: x^2 - 3x + 2 can be factored as (x - 1)(x - 2)
Denominator: x^2 - 4 can be factored as (x + 2)(x - 2)
Therefore, the equation becomes:
(x - 1)(x - 2) / (x + 2)(x - 2) = 0
Now, we can simplify this by cancelling out the common factor of (x - 2) in the numerator and denominator:
(x - 1) / (x + 2) = 0
To find the values of x that satisfy this equation, we set the numerator equal to zero:
x - 1 = 0
x = 1
Therefore, the solution to the equation x^2 - 3x + 2 / x^2 - 4 = 0 is x = 1.