To solve the system of equations, we can use the method of substitution or elimination.
Let's first solve the system of equations using the substitution method:
From the first equation: 4x + 5y = 1 Rearranging the equation, we get: y = (1 - 4x) / 5
Substitute y in the second equation: 5x + 7(1 - 4x) / 5 = 5 5x + 7 - 28x / 5 = 5 Multiplying everything by 5 to get rid of the fractions: 25x + 35 - 28x = 25 25x - 28x = 25 - 35 -3x = -10 x = (-10 / -3) x = 10 / 3
Now, substitute the value of x back into the first equation to find y: 4(10 / 3) + 5y = 1 40/3 + 5y = 1 5y = 1 - 40/3 5y = 3/3 - 40/3 5y = -37/3 y = -37 / (3 * 5) y = -37 / 15
Therefore, the solution to the system of equations is: x = 10/3 and y = -37/15.
To solve the system of equations, we can use the method of substitution or elimination.
Let's first solve the system of equations using the substitution method:
From the first equation: 4x + 5y = 1
Rearranging the equation, we get: y = (1 - 4x) / 5
Substitute y in the second equation:
5x + 7(1 - 4x) / 5 = 5
5x + 7 - 28x / 5 = 5
Multiplying everything by 5 to get rid of the fractions:
25x + 35 - 28x = 25
25x - 28x = 25 - 35
-3x = -10
x = (-10 / -3)
x = 10 / 3
Now, substitute the value of x back into the first equation to find y:
4(10 / 3) + 5y = 1
40/3 + 5y = 1
5y = 1 - 40/3
5y = 3/3 - 40/3
5y = -37/3
y = -37 / (3 * 5)
y = -37 / 15
Therefore, the solution to the system of equations is:
x = 10/3 and y = -37/15.