1) 125a^3-64b^3 = (5a)^3 - (4b)^3 = (5a-4b)(25a^2 + 20ab + 16b^2)2) 1-c^3 = (1-c)(1+c+c^2)3) 8x^3-1 = (2x)^3 - 1^3 = (2x-1)(4x^2 + 2x + 1)4) t^3+1 = (t+1)(t^2 - t + 1)5) 125+a^3 = (5+a)(25-5a+a^2)6) (2x-3)^2 - 2x(4+2x) = (2x-3+2x)(2x-3-2x) = (4x-3)(-1) = -4x + 3 = 11 (c = 4)
1) 125a^3-64b^3 = (5a)^3 - (4b)^3 = (5a-4b)(25a^2 + 20ab + 16b^2)
2) 1-c^3 = (1-c)(1+c+c^2)
3) 8x^3-1 = (2x)^3 - 1^3 = (2x-1)(4x^2 + 2x + 1)
4) t^3+1 = (t+1)(t^2 - t + 1)
5) 125+a^3 = (5+a)(25-5a+a^2)
6) (2x-3)^2 - 2x(4+2x) = (2x-3+2x)(2x-3-2x) = (4x-3)(-1) = -4x + 3 = 11 (c = 4)