4x^2+1>0........................................

Предыдущий
вопрос Следующий
вопрос

To solve for x, we first want to isolate the x^2 term:

4x^2 + 1 > 0
4x^2 > -1

Now, divide both sides of the inequality by 4:

x^2 > -1/4

Since a square of a real number is always nonnegative, the inequality x^2 > -1/4 holds true for all real numbers x. This means that the original inequality 4x^2 + 1 > 0 is also true for all real numbers x.