(1/2)^2х-(1/2)х-2-32=0

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вопрос

To solve this quadratic equation, we can substitute 1/2 as a variable, say y. Therefore, the equation becomes:

y^2x - yx - 34 = 0.

This is now in the form of a quadratic equation ax^2 + bx + c = 0. To find the values of x, we can use the quadratic formula:

x = [-b ± √(b^2 - 4ac)] / 2a.

In this case, a = y^2, b = -y, and c = -34. Substituting these values into the formula, we get:

x = [y ± √(y^2 - 4y^2*(-34))] / (2y^2)
x = [y ± √(y^2 + 136y^2)] / (2y^2)
x = [y ± √(137y^2)] / (2y^2)
x = [y ± y√137] / 2y
x = (1 ± √137) / 2

Therefore, the solutions to the equation are x = (1 + √137) / 2 and x = (1 - √137) / 2.