Нок (14;26)-(11×x-23)=нод (320;280)

Предыдущий
вопрос Следующий
вопрос

First, we need to find the GCD (Greatest Common Divisor) of 320 and 280, which is 40.

Now we can rewrite the equation using the GCD:

14;26 - (11x - 23) = 40

Next, we can simplify the equation:

14;26 - 11x + 23 = 40
-11x + 37 = 40
-11x = 3
x = -3/11

Therefore, the solution to the equation is x = -3/11.