а) 2 - arccot(1/√3)
arccot(1/√3) = arctan(√3/1) = arctan(√3)Так как arctan(√3) = π/6, то получаем:
2 - arccot(1/√3) = 2 - π/6 = 12/6 - π/6 = (12 - π)/6
б) arccos(-√3/2)
Так как cos(π/6) = √3/2, то arccos(-√3/2) = π - π/6 = (6π - π)/6 = 5π/6.
Ответ:а) 2 - arccot(1/√3) = (12 - π)/6б) arccos(-√3/2) = 5π/6
а) 2 - arccot(1/√3)
arccot(1/√3) = arctan(√3/1) = arctan(√3)
Так как arctan(√3) = π/6, то получаем:
2 - arccot(1/√3) = 2 - π/6 = 12/6 - π/6 = (12 - π)/6
б) arccos(-√3/2)
Так как cos(π/6) = √3/2, то arccos(-√3/2) = π - π/6 = (6π - π)/6 = 5π/6.
Ответ:
а) 2 - arccot(1/√3) = (12 - π)/6
б) arccos(-√3/2) = 5π/6