F(x)=4-0,5x f(-1),f(0),f(1),f2

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вопрос

To find the values of f(-1), f(0), f(1), and f2, we need to evaluate the function F(x) = 4 - 0.5x at each given input value.

f(-1):
F(-1) = 4 - 0.5*(-1)
F(-1) = 4 + 0.5
F(-1) = 4.5

Therefore, f(-1) = 4.5

f(0):
F(0) = 4 - 0.5*0
F(0) = 4 - 0
F(0) = 4

Therefore, f(0) = 4

f(1):
F(1) = 4 - 0.5*1
F(1) = 4 - 0.5
F(1) = 3.5

Therefore, f(1) = 3.5

f2:
It is not clear what f2 refers to in this context. If f2 is meant to be the second derivative of F(x), we would need the original function F(x) to calculate it. If you provide more information or clarification on what f2 represents, I can assist you further.