Log2 x < logſ2^x - 12

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To solve this inequality, we need to first simplify it by using the properties of logarithms. Let's start by expressing the inequality in exponential form:

2^(log2 x) < 2^(log2(x-12))

By the property of logarithms, log_a(b) = c is equivalent to a^c = b.

So, we have:

x < x - 12

Now, let's solve for x:

x < x - 12

0 < -12

Since this last statement is not true, the inequality log2 x < log2(x - 12) has no solution.